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hambasics:sections:wavemodulationmath [2026/04/01 20:49] – [More Details: AM / FM] va7fihambasics:sections:wavemodulationmath [2026/07/10 10:31] (current) – [FM] va7fi
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-~~NOTOC~~ +====== More Optional Details ======
- +
-====== More Details: AM / FM ======+
 Here are a few more details about the AM, SSB, and FM modulation schemes introduced on the [[wavemodulation |Wave Modulation]] page. Here are a few more details about the AM, SSB, and FM modulation schemes introduced on the [[wavemodulation |Wave Modulation]] page.
  
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 Some things to try: Some things to try:
-  * Set <fc #ff0000>\$f_s\$ at 10</fc>  and <fc #4682b4>\$f_c\$ at 200</fc> and check only the transmitted signal.  You can easily imagine what the envelope (the baseband signal) should be that produced that signal.  But...+  * Set <fc #ff0000>\$f_s\$ at 10</fc>  and <fc #4682b4>\$f_c\$ at 200</fc> and check only the transmitted signal.  You can easily imagine what the envelope should be, which is what the baseband signal is.  But...
   * Decrease <fc #4682b4>\$f_c\$</fc> slowly.  At some point (around 20 or 30) the baseband signal becomes unrecoverable.  This illustrates the point that to transmit a high frequency baseband, a higher frequency carrier is needed (at least 3 to 4 times the frequency of the baseband signal.  This is why with digital signals, the higher the transfer speed, the higher the carrier frequency needs to be.   * Decrease <fc #4682b4>\$f_c\$</fc> slowly.  At some point (around 20 or 30) the baseband signal becomes unrecoverable.  This illustrates the point that to transmit a high frequency baseband, a higher frequency carrier is needed (at least 3 to 4 times the frequency of the baseband signal.  This is why with digital signals, the higher the transfer speed, the higher the carrier frequency needs to be.
  
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 <WRAP round alert box center 80%> <WRAP round alert box center 80%>
-Now, it might be tempting to simply substitute this sum in the wave like so:+It might be tempting to simply substitute this sum in the wave like so:
  
 \$$ \cos(2\pi f_c t) \quad \rightarrow \quad \cos\Big(\big(2\pi f_c + 2\pi k s(t)\big) t\Big) \$$ \$$ \cos(2\pi f_c t) \quad \rightarrow \quad \cos\Big(\big(2\pi f_c + 2\pi k s(t)\big) t\Big) \$$
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 </WRAP> </WRAP>
  
-To solve this properly, we need some calculus and deduce the angle from our new frequency:+To solve this properly, we need some calculus to deduce the angle from our new frequency:
  
 \$$ \frac{d}{dt}\theta(t) = 2\pi f_c + 2\pi k s(t) \qquad  \Rightarrow \qquad \theta(t) = 2\pi f_c t + 2\pi k \int_0^{t}s(\tau) d\tau \$$ \$$ \frac{d}{dt}\theta(t) = 2\pi f_c + 2\pi k s(t) \qquad  \Rightarrow \qquad \theta(t) = 2\pi f_c t + 2\pi k \int_0^{t}s(\tau) d\tau \$$
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 Some things to try: Some things to try:
   * Set <fc #ff0000>\$f_s\$ at 10</fc> and <fc #4682b4>\$f_c\$ at 200</fc> and check only the transmitted signal.  Notice how when the <fc #ff0000>baseband</fc> is high, the **transmitted wave** is "tight" (ie, its frequency is high), and vise-versa.  But...   * Set <fc #ff0000>\$f_s\$ at 10</fc> and <fc #4682b4>\$f_c\$ at 200</fc> and check only the transmitted signal.  Notice how when the <fc #ff0000>baseband</fc> is high, the **transmitted wave** is "tight" (ie, its frequency is high), and vise-versa.  But...
-  * Decrease <fc #4682b4>\$f_c\$</fc> slowly.  At some point (around 20 or 30) that pattern becomes unnoticeable.  Again, this illustrates the point that to transmit a high frequency baseband, a higher frequency carrier is needed (at least 3 to 4 times the frequency of the baseband signal.  This is why with digital signals, the higher the transfer speed, the higher the carrier frequency needs to be.+  * Decrease <fc #4682b4>\$f_c\$</fc> slowly.  At some point (around 20 or 30) that pattern becomes unnoticeable.  Again, this illustrates the point that to transmit a high frequency baseband, a higher frequency carrier is needed (at least 3 to 4 times the frequency of the baseband signal).  This is why with digital signals, the higher the transfer speed, the higher the carrier frequency needs to be.
   * Increase and decrease **k** to see the effect it has on the transmitted wave.  The greater **k**, the more bandwidth the resulting signal uses.  This dictates the difference between "Narrow Band FM" and "Wide Band FM".   * Increase and decrease **k** to see the effect it has on the transmitted wave.  The greater **k**, the more bandwidth the resulting signal uses.  This dictates the difference between "Narrow Band FM" and "Wide Band FM".
  
hambasics/sections/wavemodulationmath.1775101761.txt.gz · Last modified: by va7fi